Q. 11. The probability of a college student being
male is 1/3 and that of being female is 2/3. The probability
that a male student completes the course is 3/4 and
that a female student does it is 1/2. A student is
selected at random and is found to have completed
the course. What is the probability that the student
is a male? (Dec. 2001)
Solution. This problem
is based on Bayes theorem.
Let A = an event that the student completes the
course
B1 = an event that the student selected
is male
B2 = an event that the student selected
is female
Therefore, P(B1) = 1/3, P(B2)
= 2/3
P(A | B1) = 3/4, P(A | B2) =
1/2
|
P(B1) P(A | B1)
|
P(B1 | A) = |
|
|
P(B1) P(A | B1)
+ P(B2) P(A | B2)
|
|
(1/3) X (3/4)
|
or P(B1 | A) = |
|
|
[(1/3) X (3/4)] + [(2/3) X
(1/2)]
|
or P(B1 | A) = 0.428
Thus, the probability that the student being male
is 0.428.
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