The purchase inventory model with single discount may be expressed as follows:
Order Quantity | Unit Price (Rs.) |
---|---|
1 ≤ Q1 < b | P1 |
b ≤ Q2 | P2 |
Following are the steps to summarize the approach.
1. Compute the optimal order quantity for the lowest price (highest discount), i.e.,
Q2* = | (2DCo) -------------- ChP2 |
and compare the value of Q2* with the quantity b which is
required to avail the discount.
If Q2* ≥ b, then place orders
for quantities of size Q2* and obtain discount; otherwise
move to step 2.
2. Compute Q1* for price P1 and compare TC(Q1*) with TC(b). The values of TC(Q1*) and TC(b) may be determined as follows:
TC(Q1*) = | DP1 + (D/Q1*) X Co + (Q1*/2) X Ch X P1 | |
TC(b) = | DP2 + (D/b) X Co + (b/2) X Ch X P2 |
If TC(Q1*) > TC(b), then place orders for quantities of size b to get the discount.
A big cold drinks company, the Piyo - Pilao Company, buys a large number of pallets every year, which it uses in the warehousing of its bottled products. A local vender has offered the following discount schedule for pallets:
Order Quantity | Unit Price (Rs.) |
---|---|
Upto 699 | 10.00 |
700 and above | 9.00 |
The average yearly replacement is 2000 pallets. The carrying costs are 12% of the average inventory and ordering cost per order is Rs. 100.
Solution.
Given
D = 2000 pallets/year, Ch = 0.12, Co = Rs. 100,
P1 = Rs. 10, P2 = Rs. 9.00
The lowest price (highest discount) is RS. 9.00.
Q2* = | (2 X 2000 X 100) ---------------- 0.12 X 9 |
|
= 608.58 pallets/order | ||
Since Q2* < b (i.e., 608 < 700), Q2* is not feasible. | ||
Step 2 |
||
Q1* = | (2 X 2000 X 100) ---------------- 0.12 X 10 |
|
= 577.35 pallets/order |
TC(Q1*) = TC(577.35) = 2000 X10 + (2000/577.35)
X 100 + (577.35/2 ) X 0.12 X 10
= Rs. 20692.82
TC(b) = TC (700) = 2000 X 9 + (2000/700) X 100 + (700/2) X 0.12 X 9
= Rs. 18663.71
Since TC(b) < TC(Q1*) and hence the optimal order quantity is the price discount quantity, i.e., 700 units.
Order Quantity | Unit Price (Rs.) |
---|---|
1 ≤ Q1 < b1 | P1 |
b1 ≤ Q2 < b2 | P2 |
b2 ≤ Q3 | P3 |
1. Compute the optimal order quantity for the lowest price (highest discount), i.e., Q3* and compare it with b2
2. Compute Q2* and since Q3* < b2, this implies Q2* is also less than b2. Thus, either Q2* < b1 or b1 ≤ Q2* < b2
3. Compute Q1* and compare TC(b1), TC(b2) and TC(Q1*) to determine the purchase quantity.
A large dairy firm, the Cow and Buffalo Company, buys bins every year, which it uses in the warehousing of its bottled products. A local vender has offered the following discount schedule for bins:
Order Quantity | Unit Price (Rs.) |
---|---|
Upto 699 | 10.00 |
700 to 949 | 9 |
950 and above | 8 |
Solution.
Given
D = 2000 bins/year, Ch = 0.12, Co = Rs. 100, P1 = Rs. 10, P2 = Rs. 9, P3 = Rs. 8
The lowest price (highest discount) is Rs. 8. Thus calculating Q3* = corresponding to this range as follows:
Q3* = | (2 X 2000 X 100) ---------------- 0.12 X 8 |
|
= 645.49 bins/order |
Since Q3* < b2 (i.e., 645.49 < 950), go to step 2 to determine Q2*
Step 2 |
||
Q2* = | (2 X 2000 X 100) ---------------- 0.12 X 9 |
|
= 608.58 bins/order |
Again, since Q2* < b2 and b1 (i.e., 608.58 < 950 & 700) go to step 3 to calculate Q1* and compare total inventory cost corresponding to Q1*, b1 and b2.
Step 3 |
||
Q1* = | (2 X 2000 X 100) ---------------- 0.12 X 10 |
|
= 577.35 bins/order |
TC(Q1*) = TC(577.35) = 2000 X10 + (2000/577.35)
X 100 + (577.35/2 ) X 0.12 X 10
= Rs. 20692.82
TC(b1) = TC(700) = 2000 X 9 + (2000/700) X 100 + (700/2)
X 0.12 X 9
= Rs. 18663.71
TC(b2) = TC(950) = 2000 X 8 + (2000/950) X 100 + (950/2)
X 0.12 X 8
= Rs. 16666.52
The lowest total inventory cost is TC(b2) = Rs. 16666.52 and hence the optimal order quantity is the price discount quantity of 950 units, i.e., Q* = b2 = 950 units.