C program to estimate value of constant e

#include<stdio.h>
main()
{
int n,i,f=1,j;
float e = 1.0;
clrscr();
start:
printf("Enter n value: ");
scanf("%d",&n);
if(n<0)
{
printf("Please enter non-negetive value\n");
goto start;
}
for(i = 1;i<=n;i++)
{
for(j = 1;j<=i;j++)
{
f = f*j;
}
e=e+((float)1/f);
f=1;
}
printf("Result is: %f\n",(float)e);
getche();
}

Download source code here

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