Vogel Approximation Method Examples: Transportation Problem

In the previous section, we used vogel approximation method (Unit cost penalty method) to solve a transportation problem. In this section, we provide another example to enhance your knowledge.

Let's concentrate on the following example and find the optimal solution:

example Example 2 : Vogel Approximation Method

Consider the transportation problem presented in the following table:

Destination
Origin 1 2 3 Supply
1 2 7 4 5
2 3 3 1 8
3 5 4 7 7
4 1 6 2 14
Demand 7 9 18 34

Solution.

Table 1

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Destination
Origin 1 2 3 Supply Penalty
1 7 4 5 2
2 3 3 1 8 2
3 5 4 7 7 1
4 1 6 2 14 1
Demand 7 2 9 18 34  
Penalty 1 1 1    

The highest penalty occurs in the first row. The minimum cij in this row is c11 (i.e., 2). Hence, x11 = 5 and the first row is eliminated.

Now again calculate the penalty. The following table shows the computation of penalty for various rows and columns.

Final table

Destination
Origin 1 2 3 Supply Penalty
1 7 4 5 2 - - - - -
2 3 8 2 2 2 2 3 3
3 5 7 7 1 1 3 3 4 -
4 6 14 1 1 4 - - -
Demand 7 9 18 34            
Penalty 1 1 1              
2 1 1              
- 1 1              
- 1 6              
- 1 -              
- 3 -              

Initial basic feasible solution

5 X 2 + 2 X 3 + 6 X 1 + 7 X 4 + 2 X 1 + 12 X 2 = 76.

Now, you must take a break because you really deserve it. We will see you at the next section when you are ready again.

"Study little but study very thoroughly, because it is thoroughness in work which pays in the long run." -Anonymous

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